Babu bought two varieties of pulse, costing Tk. 50 and Tk. 60 per Kg. each, and mixed them in some ratio. He then sold the mixture at Tk. 70 per kg., making a profit of 20 percent. What was the ratio of the mixture?
Babu bought "x" kg of the pulse costing Tk. 50 per kg and "y" kg of the pulse costing Tk. 60 per kg.
The cost of "x" kg of the first variety = 50x Tk. The cost of "y" kg of the second variety = 60y Tk.
The total cost of the mixture = 50x + 60y Tk.
He sold the mixture at Tk. 70 per kg and made a 20 percent profit. This means he sold it for 120 percent of the cost.
Selling price of the mixture = 120% of the cost = 1.2 * (50x + 60y) Tk.
Given that he sold the mixture at Tk. 70 per kg, we can set up the equation:
1.2 * (50x + 60y) = 70 * (x + y)
Now, let's simplify this equation:
60x + 72y = 70x + 70y
Now, let's isolate the terms with "x" and "y" on one side:
60x - 70x = 70y - 72y
-10x = -2y
Now, divide both sides by -2 to solve for the ratio "x:y":
10x = 2y
x:y = 2:10
Now, simplify the ratio by dividing both parts by 2:
x:y = 1:5
So, the correct ratio of the mixture is 1:5.
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